what is the maximum speed a single ion (m= 3.82×10^-26 kg) can reach when it experiences the –0.07 V (resting) potential difference?

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  • 1 month ago
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    By work energy relation:

    =>W = ∆KE

    =>qV = 1/2mv^2

    =>1.6 x 10^-19 x 0.07 = 1/2 x 9.1 x 10^-31 x v^2

    =>v = √[2.46 x 10^10]

    =>v = 1.57 x 10^5 m/s

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