Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 month ago

I need help with this math question?

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  • 1 month ago
    Favorite Answer

    Referring to the given conditions, the angle falls in the Second Quadrant, where tan is " Negative "

    We have BC² = AC² - AB²

    =>  BC² = 25² - 7² = 576

    => BC  =  24

    Now  tan x  =  Perpendicular/Base  =  7/24

    But since tan has to be negative,

    tan x  =  - 7/24 ............... Answer

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    • Pinkgreen
      Lv 7
      1 month agoReport

      The angle x must fall in the 1 st quadrant, for
      otherwise, cos(x)=-24/25. If x falls in the 4 th
      quadrant, then sin(x)=-7/25. Now they are both +ve..

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  • sepia
    Lv 7
    1 month ago

    Given that sin x = 7/25 and cos x = 24/25, 

    find the value of (a) tan x (b) cosec x.

    (a) tan x = 7/24

    (b) cosec x = 25/7

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  • 1 month ago

    (a) tan x=sin x/cos x=(7/25)(25/24)=7/24.

    (b) csc x=1/sin x=1/(7/25)=25/7.

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  • 1 month ago

    a)

     tan(x) = sin(x)/cos(x)

    tan(x) = (7/25)/(24/25)

     = 7/25 * 25/24

     = 7/24  Answer//

    b)  csc(x) = 1/sin(x)

         = 1/7/25

        =25/7 Answer//

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  • Alan
    Lv 7
    1 month ago

    just use the formulas for tangent and cosecant

    tan(x) = sin(x)/cos(x) =  (7/25)/ (24/25) = 7/24 

    cosec(x) =  1/sin(x)  =  1/ (7/25) = 25/7  

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  • 1 month ago

    cosec = 1/sin

    tan = sin/cos

    Plug in the values....

    • Pinkgreen
      Lv 7
      1 month agoReport

      Remember that cosec, sin & cos etc. are nonsense. It must be csc x, sin x & cos x etc.

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