I need help with this math question?
- Pramod KumarLv 71 month agoFavorite Answer
Referring to the given conditions, the angle falls in the Second Quadrant, where tan is " Negative "
We have BC² = AC² - AB²
=> BC² = 25² - 7² = 576
=> BC = 24
Now tan x = Perpendicular/Base = 7/24
But since tan has to be negative,
tan x = - 7/24 ............... Answer
- sepiaLv 71 month ago
Given that sin x = 7/25 and cos x = 24/25,
find the value of (a) tan x (b) cosec x.
(a) tan x = 7/24
(b) cosec x = 25/7
- PinkgreenLv 71 month ago
(a) tan x=sin x/cos x=(7/25)(25/24)=7/24.
(b) csc x=1/sin x=1/(7/25)=25/7.
- Engr. RonaldLv 71 month ago
tan(x) = sin(x)/cos(x)
tan(x) = (7/25)/(24/25)
= 7/25 * 25/24
= 7/24 Answer//
b) csc(x) = 1/sin(x)
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- AlanLv 71 month ago
just use the formulas for tangent and cosecant
tan(x) = sin(x)/cos(x) = (7/25)/ (24/25) = 7/24
cosec(x) = 1/sin(x) = 1/ (7/25) = 25/7
- L. E. GantLv 71 month ago
cosec = 1/sin
tan = sin/cos
Plug in the values....