Help with vectors for physics homework?
2. Consider the two vectors,
A = 16.5x + 35.5y
B = 5.7x - 21y
2. A) What is the magnitude of the vector A - B?
I already found the answer to this, 57.5, but can't figure out the rest
2. B) What is the angle of the vector A - B, measured counterclockwise in degrees from the positive x-axis?
2. C) What is the magnitude of the vector 3A + B?
2. D) What is the angle of the vector 3A+B, measured counterclockwise in degrees from the positive x-axis?
2 Answers
- VamanLv 78 months ago
A = 16.5x + 35.5y
B = 5.7x - 21y
A-B= (10.8, 56.50) Magnitude =sqrt(10.8^2+56.5^2)=57.5
magnitude A=39.15, B=21.75.
cos a= A dot B/(AB)=0.06. a=1.51 degrees
Rest you can do.
- ?Lv 78 months ago
A-B = <10.8 , 56.5>
b/
angle θ , with tan(θ) = 56.5/10.8 ---> θ = 79.2 degrees
c/
3A+B = 3<16.5, 35.5> + <5.7 , -21> = <55.2 , 85.5>
--> ||3A+B||=101.8
d/
tan(θ) = 85.5/55.2 ---> θ = 57.2 degrees