An object projected upward with initial velocity Vo attains a height h.?
Another object projected up with initial velocity 2va will attain a height of (a) ½ h, (b) 3h, (c) 4h, (d) same.
- AshLv 71 month ago
s = (V₀² - V²)/2g
At max height s = h and V = 0
h = V₀²/2g
New initial velocity = 2V₀
then new height = (2V₀)²/2g = 4(V₀²/2g) = 4h
Answer (c) 4h
- Steve4PhysicsLv 71 month ago
Answer (c). 4h
Speed is doubled so the kinetic energy increases 4 times (KE = ½mv²). That means the potential energy at max. height is increased by 4 times (PE gained = KE lost). So the height increases 4 times (PE = mgh).