# Find the area of the following figure?

### 12 Answers

- 1 month ago
The diagram is a trapezium

Area of a trapezium is = Average Length of two sides multiplied by height

= 4*(10+6)/2=32

- PhilomelLv 71 month ago
If you move the left hand triangle to the other end you end up with a rectangle 8 x 4 cm.

4*8= 32 cm^2

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- PopeLv 71 month ago
There is insufficient given information to derive the area. The image suggests a trapezoid, and that was the assumption in at least five responses preceding mine, but that is not actually a given condition. We are given no reason to conclude that any two sides are parallel.

- lenpol7Lv 71 month ago
Assuming it is a symmetric trapezium, then

A = h(L + S) / 2

Where

A = area

h = perpendicular height ( 4cm)

L = longer parallel side (10 cm)

S = shorter parallel side (6 cm)

Substitute

A = 4(10 + 6) / 2

A = 2(10 + 6)

A = 2(16)

A = 32 cm^2

- llafferLv 71 month ago
The equation for the area of a trapezoid is:

A = (b₁ + b₂)h / 2

We have values for all three unknowns. Substitute and simplify:

A = (10 + 6)(4) / 2

A = 16(4) / 2

A = 64 / 2

A = 32 cm²