Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 month ago

# Find the area of the following figure?

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• 1 month ago

The diagram is a trapezium

Area of a trapezium is  = Average Length of two sides multiplied by height

= 4*(10+6)/2=32

• 1 month ago

A = 1/2h(a + b)

A = 1/2(4)(10 + 6)

A = 32 cm^2 Answer..//

• 1 month ago

If you move the left hand triangle to the other end you end up with a rectangle 8 x 4 cm.

4*8= 32 cm^2

• 1 month ago

Area=(6+10)*4/2=32 cm^2

• Pope
Lv 7
1 month ago

There is insufficient given information to derive the area. The image suggests a trapezoid, and that was the assumption in at least five responses preceding mine, but that is not actually a given condition. We are given no reason to conclude that any two sides are parallel.

• sepia
Lv 7
1 month ago

A = (6 + 24 + 2) cm^2 = 32 cm^2

• 1 month ago

The area of the given figure is 32 cm^2.

• 1 month ago

Assuming it is a symmetric trapezium, then

A = h(L + S) / 2

Where

A = area

h = perpendicular height ( 4cm)

L = longer parallel side (10 cm)

S = shorter parallel side (6 cm)

Substitute

A = 4(10 + 6) / 2

A = 2(10 + 6)

A = 2(16)

A = 32 cm^2

• 1 month ago

The equation for the area of a trapezoid is:

A = (b₁ + b₂)h / 2

We have values for all three unknowns.  Substitute and simplify:

A = (10 + 6)(4) / 2

A = 16(4) / 2

A = 64 / 2

A = 32 cm²

• Robert
Lv 7
1 month ago

It would have been easier to