How does a force from one cable transfer to four other cables?
The problem is that there is a frame being dragged by a single cable with a force of 22000N. The cable gets split up into four other cables and they get connected to the frame. The system is moving at a constant speed of 2 m/s (reached equilibrium). How can I calculate the forces in the four cables?
- NCSLv 71 month ago
I'll assume that the red line is the line of action of the applied force. Then for vertical equilibrium,
2*F₁*sin19.4º*cos30º = 2*F₂*sin2.5º*cos32.2º
For horizontal equilibrium,
2*F₁*cos19.4º*cos30º + 2*F₂*cos2.5º*cos32.2º = 22000 N
Two equations, two unknowns.
F₁ = 1484 N
F₂ = 11578 N
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