Calculus question U subs integral?
∫ 15r^4 dr/sqrt(2-r^5),u=2-r^5
- AmyLv 74 weeks ago
u = 2-r^5
du = -5r^4 dr
∫ 15r^4 dr / √(2-r^5) = ∫ -3du / √u
= 6 √u
= 6 √(2-r^5)
- rotchmLv 74 weeks ago
u = 2 - r^5 --> du = -5 r^4 dr.
So your integrand is now: 15 * (du / -5) / √u. You can simplify this a little further.
Note that up to this point, it was just highschool algebra!
Then integrate since its of the form uⁿ.