Calculus question U subs integral?

 ∫ 15r^4 dr/sqrt(2-r^5),u=2-r^5

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  • Amy
    Lv 7
    4 weeks ago

    u = 2-r^5

    du = -5r^4 dr

    ∫ 15r^4 dr / √(2-r^5) = ∫ -3du / √u

    = 6 √u

    = 6 √(2-r^5)

  • rotchm
    Lv 7
    4 weeks ago

    u = 2 - r^5 --> du = -5 r^4 dr.

    So your integrand is now:  15 * (du / -5) / √u. You can simplify this a little further.

    Note that up to this point, it was just highschool algebra! 

    Then integrate since its of the form uⁿ. 

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