Anonymous
Anonymous asked in Science & MathematicsChemistry · 4 weeks ago

When zinc metal is placed in a solution of copper (II) nitrate, a solid precipitate forms according to the following reaction equation:?

When zinc metal is placed in a solution of copper (II) nitrate, a solid precipitate forms according to the following reaction equation: 

Zn (s) + Cu(NO3)2 (aq) --> Cu (s) + Zn(NO3)2 (aq)

The mass of solid precipitate formed when 50.0mL of 0.250 mol/L copper (II) nitrate solution completely reacts with zinc metal is:

A) 0.817g of Cu(s)

B) 794g of Cu(s)

C) 0.794g of Cu(s)

D) 0.794g of Zn(s)

1 Answer

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  • 4 weeks ago
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    (0.050 L) x (0.250 mol/L Cu(NO3)2) x (1 mol Cu / 1 mol Cu(NO3)2) x

    (63.5463 g Cu/mol) = 0.794 g Cu

    So answer C).

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