Can someone help me with these chemistry lab questions?
1. It takes 76 mL of a 0.43 M KOH solution to neutralize 238 mL of an HCl solution. What is the concentration of the HCl solution?
2. If blood had a normal pH of 6.1 instead of 7.4, would you expect exercise to result in heavy breathing? Please justify your answer.
3. How would a titration curve like the one depicted in Figure 4 differ from a sulfuric acid strong base titration? Remember, the graph in Figure 4 only shows the titration of carbonic acid to yield bicarbonate.
4. You are titrating an acid into a base to determine the concentration of the base. The endpoint of the neutralization is reached but the stopcock on the buret sticks slightly and allows a few more drops of acid to fall into the solution. How will this affect your calculations for the concentration of the base?
- Roger the MoleLv 74 weeks agoFavorite Answer
HCl + KOH → KCl + H2O
(76 mL) x (0.43 M KOH) x (1 mol HCl / 1 mol KOH) / (238 mL HCl) = 0.14 M HCl