Anonymous
Anonymous asked in Science & MathematicsPhysics · 4 weeks ago

a 38.5 kg man is in an elevator accelerating downward. A normal force of 343 N pushes up on him. What is his acceleration?

3 Answers

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  • 4 weeks ago

    For downward motion of a lift:

    =>F(net) = F(gravity) - F(applied)

    As N = mg (Apparent) = F(net)

    =>343 = 38.5 x 9.81 - 38.5 x a

    =>a = 0.90 m/s^2 {downward}

     

  • 4 weeks ago

    I'll take up as positive and use g = -9.81m/s².

    His weight: W = mg = 38.5*(-9.81) = -377.685N

    Resultant force on man: F = (-377.685) + 343 = -34.685N

    F=ma gives:

    a = F/m = -34.685/38.5 = -0.901 m/s² to 3 sig. figs.

    So his acceleration is 0.901m/s² downwards.

  • 4 weeks ago

    F = m*(g - a)

    a = 9,81 - (343/38,5) = 8,91 m/s²

    Review it!

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