# Find the amount of heat energy needed to convert 400 grams of ice at -38°C to steam at 160°C.?

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- Roger the MoleLv 72 months ago
(2.087 J/(g·°C)) x (400 g) x (0 - (-38))°C =

31722.4 J to warm the ice to its melting point

(333.6 J/g) x (400 g) = 133440 J to melt the ice

(4.184 J/(g·°C)) x (400 g) x (100 - 0)°C =

167360 J to warm the melted ice to its boiling point

(2257 J/g) x (400 g) = 902800 J to vaporize the water

(2.000 J/(g·°C)) x (400 g) x (160 - 100)°C = 48000 J to heat the steam to 160°C

31722.4 J + 133440 J + 167360 J + 902800 J + 48000 J = 1283322.4 J =

1283 kJ total

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