Anonymous

# Physics question?

While traveling at constant speed in an airplane, a passenger’s weight is 750 N.

When the airplane accelerates downwards, his apparent weight is 672 N. What

was the acceleration of the airplane?

### 3 Answers

Relevance

- NCSLv 72 months ago
For an object accelerating in the direction of a gravitational field, the required force is

F = m*(g - a)

so here

672 N = (750N / 9.8m/s²) * (9.8m/s² - a)

a = 1.02 m/s²

down

- Andrew SmithLv 72 months ago
mg=750; m(g-a) = 672 -> (g-a)/g= 672/750 -> 1- a/g = 672/750

-> a = g*(1-672/750)

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