Anonymous
Anonymous asked in Science & MathematicsPhysics · 2 months ago

Physics question?

While traveling at constant speed in an airplane, a passenger’s weight is 750 N.

When the airplane accelerates downwards, his apparent weight is 672 N. What

was the acceleration of the airplane?

3 Answers

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  • NCS
    Lv 7
    2 months ago

    For an object accelerating in the direction of a gravitational field, the required force is

    F = m*(g - a)

    so here

    672 N = (750N / 9.8m/s²) * (9.8m/s² - a)

    a = 1.02 m/s²

    down

  • oubaas
    Lv 7
    2 months ago

    AW = m*(g+a) 

    672 = 750+750/9,807*a

    a = (-750+672)*9.807/750 =  -1.02 m/sec^2 

  • 2 months ago

    mg=750;   m(g-a) = 672  -> (g-a)/g= 672/750  -> 1- a/g = 672/750

    -> a = g*(1-672/750)

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