While traveling at constant speed in an airplane, a passenger’s weight is 750 N.
When the airplane accelerates downwards, his apparent weight is 672 N. What
was the acceleration of the airplane?
- NCSLv 72 months ago
For an object accelerating in the direction of a gravitational field, the required force is
F = m*(g - a)
672 N = (750N / 9.8m/s²) * (9.8m/s² - a)
a = 1.02 m/s²
- oubaasLv 72 months ago
AW = m*(g+a)
672 = 750+750/9,807*a
a = (-750+672)*9.807/750 = -1.02 m/sec^2
- Andrew SmithLv 72 months ago
mg=750; m(g-a) = 672 -> (g-a)/g= 672/750 -> 1- a/g = 672/750
-> a = g*(1-672/750)