# By mixing 15.0mL of 0.325M sodium phosphate with 35.0mL of 0.0225M potassium sulphate,?

a) Write a dissociation equation for each solutions.

b) Will there be a precipitate? Write a net ionic equation if there is.

c) Find the final total ion concentration.

### 1 Answer

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- Roger the MoleLv 72 months ago
a)

Na3PO4 → 3 Na{+} + PO4{3-}

K2SO4 → 2 K{+} + SO4{2-}

b)

There will be no precipitate.

c)

(0.0150 L) x (0.325 mol Na3PO4/L) x (4 mol ions / 1 mol Na3PO4) =

0.0195 mol ions from Na3PO4

(0.0350 L) x (0.0225 mol K2SO4/L) x (3 mol Ions / 1 mol Na2SO4) =

0.0023625 mol ions from Na2SO4

Supposing additive volumes:

(0.0195 mol ions + 0.0023625 mol ions) / (0.0150 L + 0.0350 L) =

0.437 mol/L ions total

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