Ryan asked in Science & MathematicsEngineering · 2 months ago

The question goes like this:

A 25 Ω, 50 Ω, and 100 Ω set of resistors were used to create the following conditions:

• Current coming out of the battery, I = 0.86A

• Voltage across the 50 Ω resistor is 28.57 V

Reconstruct the circuit responsible for the above parameters.That's all the information that is provided to the question- no diagram nor anything else.

Update:

nevermind i figured it out thx anyways

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• 2 months ago

You already have the answer but didn't show anyone else how you got it.  Here is how I got it:   We know the ckt won't be all the resistors in series because the current in the 50Ω = 28.57V/50Ω = 0.5714A and that is not 0.86A out of the battery. Therefore we know there must be 2 resistors in parallel fed by a resistor in series with the voltage source. I tried the 25Ω in series with a voltage source connected to the 50Ω in parallel with the 100Ω.So the 100Ω has current = 28.57/100 = 0.2857A

The 50Ω has 28.57V/50Ω = 0.5714A.

0.2857+0.5714 = 0.8571 or about 0.86A out of the source which checks.  What is the voltage of the source?

0.86*25Ω+28.57V = 50V. The ckt is

+50V in series with 25Ω connected to 50Ω||100Ω and then back to the negative of the 50V source.

.

• 2 months ago

i= v/r

0.86=v/(100+50+25)

v=150.6