A skydiver is falling through air at a speed that is one fifth of their eventual terminal speed. ?
What is the acceleration at this instant in terms of g, the acceleration of gravity? Assume that their cross-sectional area, drag coefficient, and density of air remain constant.
- Dr. ZorroLv 75 months ago
m a = m g - c v^2
Terminal velocity (a=0) is given by
V = sqrt(m g / c)
Taking v = V/5 gives
m a = = m g - 1/25 m g
a = 24/25g = 0.96 g