Sam asked in Science & MathematicsPhysics · 2 months ago

Suppose that Box 2 with a mass of 2.5 kg is on top of box 1 with a mass of 3.5 kg.?

Attachment image

1 Answer

Relevance
  • NCS
    Lv 7
    2 months ago

    The system acceleration is

    a = F / M = 14N / 6kg = 2.33 m/s²

    For box 1 to accelerate at that rate, the friction force motivating it must be

    f = 3.5kg * 2.33m/s² = 8.2 N ◄

    As a check, consider again box 2. The net force on it would be

    Fnet = (14 - 8.2)N = 5.8 N

    and so its acceleration is

    a = 5.8N / 2.5kg = 2.33 m/s² √√√

    If you find this helpful, please select Favorite Answer. You get points too!

Still have questions? Get your answers by asking now.