# Suppose that Box 2 with a mass of 2.5 kg is on top of box 1 with a mass of 3.5 kg.?

### 1 Answer

Relevance

- NCSLv 72 months ago
The system acceleration is

a = F / M = 14N / 6kg = 2.33 m/s²

For box 1 to accelerate at that rate, the friction force motivating it must be

f = 3.5kg * 2.33m/s² = 8.2 N ◄

As a check, consider again box 2. The net force on it would be

Fnet = (14 - 8.2)N = 5.8 N

and so its acceleration is

a = 5.8N / 2.5kg = 2.33 m/s² √√√

If you find this helpful, please select Favorite Answer. You get points too!

Still have questions? Get your answers by asking now.