Jason asked in Science & MathematicsPhysics · 2 months ago

1. An electron moving at 7.5 106 m/s enters an electric field between parallel plates by passing through a small hole in one of the plates?

Attachment image

1 Answer

Relevance
  • 2 months ago

    Initial kinetic energy = ½mv² =  ½*9.11*10^31*(7.5*10^6)² = 2.56*10^-17J

    Kinetic energy gained by going through 250V is qV = 1.6*10^-19*250 = 4*10^-17J

    Total final energy E = 4*10^-17 + 2.56*10^-17 = 6.56*10^-17J

    If final velocity is V then E = ½mV²

    V = √[2E/m] = √[2 * 6.56*10^-17 / (9.11*10^-31)] = 1.2*10^7 m/s

Still have questions? Get your answers by asking now.