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# Solve the triangle using the Law of sines or the Law of cosines given the following:?

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- 1 month agoFavorite Answer
6^2 = 3^2 + 5^2 - 2 * 3 * 5 * cos(C)

36 = 9 + 25 - 30 * cos(C)

30 * cos(C) = 34 - 36

30 * cos(C) = -2

cos(C) = -2/30

cos(C) = -1/15

C = arccos(-1/15)

3^2 = 5^2 + 6^2 - 2 * 5 * 6 * cos(A)

9 = 25 + 36 - 60 * cos(A)

60 * cos(A) = 61 - 9

60 * cos(A) = 52

15 * cos(A) = 13

cos(A) = 13/15

A = arccos(13/15)

That's as exact as either can get.

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