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# Trick Trig Question!!!?

angles α and β are obtuse angles in quadrant II. if cscα=3 and β=-1/3, determine the exact value of cos(α+β)

Someone PLEASE find the answer and explain how to solve it thoroughly too.

### 2 Answers

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- alexLv 72 months agoFavorite Answer
What's "β=-1/3"

α and β are obtuse angles in quadrant II---> sin α >0 , cos α<0 , also sin β >0 , cos β<0identity (sinx)^2+(cosx)^2=1

and

cos(α+β)=cos(α)cos(β)-sin(α)sin(β)

You can do with all the given information

- ♥Astrid♥Lv 72 months ago
Your question statement has to be wrong. "β = -1/3" makes no sense at all, that would land the angle in quadrant IV, and you said initially that both angles were in quadrant II.

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