How do I solve this?

Find the area of triangle ABC with the given parts. Round to one decimal place.

A = 34°40'

b = 16.8 m

c = 11.7 m

2 Answers

Relevance
  • 1 month ago

    Area of ΔABC

    = (1/2) b c sin(A)

    = (1/2) × 16.8 × 11.7 × sin(34°40') m²

    = 55.9 m²

  • If you have 2 sides and the angle between them, then the area is:

    (1/2) * s[1] * s[2] * sin(T)

    (1/2) * 16.8 * 11.7 * sin(34 degrees 40 minutes)

    34 degrees 40 minutes =>

    34 degrees + 40/60 degrees =>

    34 + 2/3 degrees =>

    (34 * 3 + 2) / 3 degrees =>

    104/3 degrees

    (1/2) * 16.8 * 11.7 * sin(104/3 degrees)

    Make sure your calculator is in degree mode

    55.90177437854827302547316899135...

    To 1 decimal place

    55.9 square meters

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