Kohul asked in Science & MathematicsPhysics · 5 months ago

A double-slit apparatus is held 1.2m from a screen. When red light(600nm) is sent through the double slit, the interference pattern shows a?

a distance of 12.5cm between the 1st and 10th dark fringes. What is the separation of the slits?

What will be the difference in path length for the waves traveling from each slit to the tenth nodal line?

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  • 5 months ago
    Favorite Answer

    y = m*wl*d/a  where m = 1, 2, 3,..., wl = wavelength, d = distance from slits to screen, a = distance between slits

    delta_y = y(m) - y(n) = wl*d/a*(m - n)

    So for a given everything else --->  a = wl*d*(m-n)/delta_y = 600x10^-9(m)*1.2(m)*(10 - 1)/(0.125 (m)) = 5.184x10^-5 m

  • Lv 7
    5 months ago

    you should ask your teacher. unless you want to pay us what you pay him...

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