A weather balloon has a volume of 35 L at sea level (1.0 atm). After the balloon is released it rises to where the air pressure is 0.75 atm.?

What will the new volume of the weather balloon be?

2 Answers

  • 5 months ago
    Favorite Answer

    Boyle's Law pV=const

    p1 V1 = p2 V2

    V2 = (p1/p2) V1

    V2 = (1/0.75)*35 = (4/3)*35 = 46.7 L

  • 5 months ago


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