a asked in Science & MathematicsPhysics · 2 months ago

physics help?

An arrow of mass 0.018 kg is shot upward at an angle from the ground, reaching a maximum height of 25 m with a speed of 62 m/s. Neglecting air resistance, with what speed will the arrow hit the ground?

3 Answers

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  • 2 months ago
    Favorite Answer

    Energy is conserved.  The energy at the top is equal to the energy when it hits the ground.  so 1/2 m * 62^2 + m g * 25 = 1/2 m v^2

    divide by m and multiply by 2  62^2 + 2  9.8 * 25 = v^2

    v = sqrt( 62^2 + 50 * 9.8)  ~ 65.8 m/s

  • Ash
    Lv 7
    2 months ago

    The arrow will hit the ground at the same speed it was shot from the ground.

    i.e. 62 m/s

  • Use energy to solve

    Potential Energy = Kinetic Energy

    mgh = 0.5mv²

    gh = 0.5v²

    v = √(2gh)

    v = √(2*10*25)

    v = 22.2 

    Of course, I have no clue what I'm doing

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