What volume is occupied by 2 moles of nitrogen gas at a temperature of 73 °F and a pressure of 238.0 psi?
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- hcbiochemLv 76 months ago
(73F - 32) X 5/9 + 273.15 = 295.93 K
238.0 psi /14.696 psi/atm = 16.19 atm
PV = n RT
V = (2 mol) (0.08206 Latm/molK) (295.93 K) / 16.19 atm = 3 L
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