What is the change in entropy of 1.00 kg of liquid water at 100°C as it changes to steam at 100°C?  Has to be in J/K ?

What is the change in entropy of 1.00 kg of liquid water at 100°C as it changes to steam at 100°C?

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  • 1 month ago

    ΔS = ∫︎ dQ / T

    Note that during a phase transition T is constant, so 1/T can be taken out in front of the integration. The integral of dQ will add up to the heat of vaporization of 1kg of water, L.

    So 

    ΔS = L / T 

    L = 2.260kJ/kg * 1.00kg = 2260 J

    T = 373 K

    ΔS = 2260J / 373K = 6.05 J/K

  • 1 month ago

    A revolution.ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

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