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# Math Questions?

I couldn't do this question. Can anyone answer this question?

### 1 Answer

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- stanschimLv 75 months ago
ln(y) = (3/4)ln(x) + (1/2)ln(x^2 + 2) - (1/5)ln(x + 3)

(1/y)(dy/dx) = (3/4)(1/x) + x/(x^2 + 2) - (1/5)(1/(x + 3))

dy/dx = y[(3/4)(1/x) + x/(x^2 + 2) - (1/5)(1/(x + 3))]

You can substitute the original y in terms of x from your problem statement to get the answer. You may be able to simplify the terms from there.

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