A train car with mass m1 = 529 kg is moving to the right with a speed of v1 = 8.1 m/s and collides with a second train car.?
A train car with mass m1 = 529 kg is moving to the right with a speed of v1 = 8.1 m/s and collides with a second train car. The two cars latch together during the collision and then move off to the right at vf = 5.2 m/s.
1)What is the initial momentum of the first train car?
2)What is the mass of the second train car?
3)What is the change in kinetic energy of the two train system during the collision?
4)Now the same two cars are involved in a second collision. The first car is again moving to the right with a speed of v1 = 8.1 m/s and collides with the second train car that is now moving to the left with a velocity v2 = -6 m/s before the collision. The two cars latch together at impact.
What is the final velocity of the two-car system? (A positive velocity means the two train cars move to the right – a negative velocity means the two train cars move to the left.)
5)Compare the magnitude of the momentum of train car 1 before and after the collision:
p1 initial = p1 final
p1 initial > p1 final
p1 initial < p1 final
- NCSLv 75 months agoFavorite Answer
3) change in KE
½*[(529+295)kg*(5.2m/s)² - 529kg*(8.1m/s)²] = -6213 J
indicating a loss of KE
4) conserve momentum
529kg*8.1m/s + 295kg*-6m/s = 824kg * V
V = 3.05 m/s
5) Clearly p1 initial > p1 final
Hope this helps!
- JimLv 75 months ago
Momentum formua is P=mv
KE = 1/2 mv²
simply insert your values.