Calculate Kp?

The answer is 2.53x10^-5

Anyone knows how to solve it?

Thanks

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  • 3 months ago
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    In the heterogeneous equilibrium, only the partial pressures of the gaseous components are involved in the equilibrium expression.

                       2 MgO(s) + 2Cl₂(g) ⇌ 2MgCl₂(s) + O₂(g)

    Initial:                             1 mol                          0 mol

    Change:                      -0.3 mol                    +0.15 mol

    Equilibrium:                  0.7 mol                      0.15 mol

    Partial pressure of Cl₂, 𝑃Cl₂ = (1.00 × 10⁵ Pa) × [0.7/(0.7 + 0.15)]= 82350 Pa

    Partial pressure of O₂, 𝑃O₂ = (1.00 × 10⁵ Pa) × [0.15/(0.7 + 0.15)] = 17650 Pa

    Kp = 𝑃O₂/𝑃Cl₂² = (17650 Pa) / (82350 Pa)² = 2.60 × 10⁻⁵ Pa⁻¹

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