# Could someone please help me with this math problem?

The question gives me this hill function: y= Ax^n/(k^n+x^n)

The question is as so: For what positive value(s) of x does y achieve half its value at the horizontal asymptote?

### 1 Answer

Relevance

- Anonymous1 month agoFavorite Answer
I'll assume n>1.

For large values of x, k^n becomes negligible compared to x^n and we get:

y = Ax^n/x^n = A

So y=A is the horizontal asymptote.

When y = A/2:

A/2= Ax^n/(k^n+x^n)

k^n+x^n = 2x^n

k^n = x^n

x = k

Still have questions? Get your answers by asking now.