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- ?Lv 74 months ago
The formula of a parabola in vertex form can be represented as

y = a(x - h)² + k

vertex is (h, k)

From the graph, the vertex is (3, 6)

(y - y_0)^2 = 4 a (x - x_0)

(y - 6)^2 = 4 a (x - 5)

y = 4 (a x - 5 a + 9)

- AshLv 74 months ago
A formula of parabola in vertex form can be represented as

y = a(x-h)² + k

vertex is (h,k)

From graph vertex is (3,6)

y = a(x-3)² + 6

since the parabola passes through point (5,11), it should should satisfy the equation

11 = a(5-3)² + 6

5 = 4a

a = 5/4

so the equation becomes

y = (5/4)(x-3)² + 6

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