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- NCSLv 73 months agoFavorite Answer
k = ΔF / Δx = (500 - 0)N / (37.6 - 35)mm = 192 N/mm

energy E = ½k(Δx)²

and at T = 400 N, x ≈ 37 mm

and so Δx ≈ (37 - 35) mm = 2 mm

E = ½ * 192N/mm * (2mm)² * 1m/1000mm = 0.384 J

and so I'd go with choice A.

Hope this helps!

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