Can someone please help me with this physics problem?
A U-tube of uniform cross section is partly filled with water (density ρW). Another liquid of density ρ that does not mix with water is poured into one side until it stands a distance d above the original water level. The water level rises by a distance l in the other arm (see the figure below). If d=9 cm and l=2 cm, what is the density of the liquid relative to that of water?
- NCSLv 71 month agoFavorite Answer
The pressure at the level of the bottom of the "liquid of density ρ" is the same on both sides of the apparatus.
pressure = ρgh
and so on the left side we have
p = ρ*g*(d+ℓ)
and on the right side
p = ρw*g*2ℓ
equating the two and canceling g we get
ρ*(d+ℓ) = ρw*2ℓ
ρ / ρw = 2ℓ / (d+ℓ) = 2*2 / (9+2) = 4/11 = 0.36
and we call this ratio the specific gravity.
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- ?Lv 71 month ago
Yes, the people that solved similar examples that you can find on the internet or in your textbook.