Is there a trick to graph this function?
Short of trying to grab a ruler and plot it on my computer screen. The Y axis does not have hash marks.
- RockItLv 71 month ago
I notice the graph is of the form y = -a(x-h)^2, i.e. the "trick" is that its y=-ax^2 translated to the right giving rise to: h=4 and a=-4 by factoring. y=-4(x-4)^2 with 2 positive identical roots.
- MorningfoxLv 71 month ago
No "trick". Just find the y values for x = 2, 3, 4, 5, and 6
- JimLv 71 month ago
We know from Quardratic that vertex is at x = -b/2a = -32/-8 = 4
Subbing in x=4
y = -4(16) +32x - 64 so y= 0
2 same real solutions (4,0), (4,0)
There is no reason for 'y' axis to have values.