Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 month ago

Help please?

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  • Dr W
    Lv 7
    1 month ago

    if NH3 is the LR

    .. 150g NH3*(1mol / 17.02g)*(4mol NO/4mol NH3)*(30.01gNO/mol) = 264g NO

    if O2 is the LR

    .. 150g O2*(1mol / 32.00g)*(4mol NO/5mol O2)*(30.01gNO/mol) = 112.5g NO

    since O2 gave less NO, O2 is the LR and the theoretical yield = 112.5g NO

    % yield = (87g / 112.5g) * 100%) = 77%

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