Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 month ago

Valence electrons ?

Would it be 7?

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  • 1 month ago

    Formal charge on O in

    Na−O−CH3 ............... oxygen has two lone pairs

    Formal charge = VE - NBE - ½BE

    VE = valence electrons, NBE = nonbonding electrons, BE=bonding electrons

    FC = 6 - 4 - 2 = 0

    The number of valence electrons for oxygen is ALWAYS 6.

  • 1 month ago

    Oxygen has 6 valence electrons.

    This is an ionic compound and so the Na+ has a +1 charge and no valence electrons. To calculate the formal charge on O,

    Formal Charge = Valence electrons - non-bonding electrons - 1/2 bonding electrons

    Formal Charge = 6 - 6 - 1/2(2) = -1

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