Valence electrons ?
Would it be 7?
- pisgahchemistLv 71 month ago
Formal charge on O in
Na−O−CH3 ............... oxygen has two lone pairs
Formal charge = VE - NBE - ½BE
VE = valence electrons, NBE = nonbonding electrons, BE=bonding electrons
FC = 6 - 4 - 2 = 0
The number of valence electrons for oxygen is ALWAYS 6.
- hcbiochemLv 71 month ago
Oxygen has 6 valence electrons.
This is an ionic compound and so the Na+ has a +1 charge and no valence electrons. To calculate the formal charge on O,
Formal Charge = Valence electrons - non-bonding electrons - 1/2 bonding electrons
Formal Charge = 6 - 6 - 1/2(2) = -1