Physics question ?
A proton gains 1.76 x 10-15 J of kinetic energy as it passes through an electric field. Calculate the potential difference causing its acceleration.
I am not sure how to answer this one...
- AshLv 74 weeks agoFavorite Answer
KE = qΔV
ΔV = KE/q
ΔV = (1.76 x 10⁻¹⁵ J)/(1.602×10−19 C)
ΔV = 1.10 x 10⁴ V