Anonymous
Anonymous asked in Science & MathematicsMathematics · 4 weeks ago

Math/Algebra?

Find the equation for the circle with center (5,3) and passing through (2,-2).

Write the equation for the circle. Simplify your answer.

2 Answers

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  • 4 weeks ago

    The equation of a circle with centre (a, b) and radius r is (x - a)^2 + (y - b)^2 = r^2

    So we have:

    (x - 5)^2 + (y - 3)^2 = r^2

    Radius, r, is the distance between the two points. 

    r= sqrt [(2−5)^2+(−2−3)^2]

    r= sqrt [(−3)^2+(−5)^2]

    r= sqrt (9+25)

    r= sqrt( 34)

    r^2 = 34

    We now have: (x - 5)^2 + (y - 3)^2 = 34

  • ted s
    Lv 7
    4 weeks ago

    ( x - 5 ) ² + ( y - 3 )² = (5-2)² + (3 - (-2))²

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