A pitcher throws a ball horizontally. It falls 83cm while traveling 14.8m to home plate. Ignoring air resistance, find initial horizontal?
the initial horizontal speed of the baseball.
- oldschoolLv 72 months agoFavorite Answer
Let t be the time to home plate. We know 0.83m = ½*g*t² and Vx*t = 14.8m so
t = 14.8/Vx Substitute into first eq.0.83 = ½*g* (14.8/Vx)²
Vx² = 4.9*14.8²/0.83 = 36²
Vxi = Vx = 36m/s and is assumed constant neglecting air resistance.