# A 1.50 x 10^-5 C charge feels a 2.89 x 10^-3 N force when it moves 288 m/s perpendicular (90°) to a magnetic field. How strong is the field?

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- oldschoolLv 71 month ago
F =qV x B = qVBsinΘ with Θ = 90°

F/qVsinΘ = B = 2.89e-3/(1.5e-5* 288*sin90) = 0.669 T

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