# What is the average force on the bullet as it moves down the barrel? ?

A 7.58- g bullet is moving at 538.00 m/s as it leaves the 0.57- m-long barrel of a rifle. What is the average force on the bullet as it moves down the barrel? Assume that the acceleration is constant.

### 1 Answer

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- SpacemanLv 74 weeks ago
m = mass of bullet = 7.58 g = 0.00758 kg

Δx = length of barrel = 0.57 m

v0 = initial velocity of bullet = 0 m/s

v = final velocity of bullet = 538.00 m/s

a = constant acceleration = to be determined

F = applied force on bullet = to be determined

Δx = 0.5t(v + v0)

Δx / 0.5(v + v0) = t

t = Δx / 0.5(v + v0)

t = 0.57 m / 0.5(538.00 m/s + 0 m/s)

t = 0.002118959 s

v = v0 + at

v - v0 = at

(v - v0) / t = a

a = (v - v0) / t

a = (538.00 m/s - 0 m/s) / 0.002119 s

a = 253,898 m/s²

F = ma

F = (0.00758 kg)(253,898 m/s²)

F = 1,925 N = 1.9 kN Average Force on Bullet

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