Anonymous

# Physics question - look at photo?

Let me know all three parts please

### 3 Answers

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- NCSLv 74 weeks agoFavorite Answer
001/

v² = u² + 2ah = (45m/s)² + 2 * 2.43m/s² * 211.7m = 3054 m²/s²

max height

h = h0 + v² / 2g = 211.7m + 3054m²/s² / 19.6m/s² = 367.5 m

002/

during powered phase

h = v0*t + ½at²

211.7 = 45t + ½*2.43*t²

has a positive root at t = 4.22 s

during unpowered rise

t' = v/g = √3054 / 9.8 s = 5.64 s

for a total ascent time of 9.86 s

003/ time to fall from 367.5 m is

t" = √(2h/g) = √(2 * 367.5m / 9.8m/s²) = 8.66 s

for a total flight time of 18.5 s

Hope this helps!

- Anonymous4 weeks ago
It’s for homework. What test would be happening on a Sunday? Lmao

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