A hydrogen atom emits a photon as its electron changes from n = 7 to n = 2. For the H atom, En = -2.18E-18*(1/n2) J.?
What is the wavelength (in m) of the photon?
In what region of the electromagnetic spectrum is this photon found? Please enter the full name of the spectral region - infrared, visible (400-700 nm) or ultraviolet.
- hcbiochemLv 74 months agoFavorite Answer
Delta E = -2.18X10^-18 (1/n^2f - 1/n^2i)
Delta E = -2.18X10^-18 (1/4 - 1/49) = -5.00X10^-19 J/photon
E = hc/wavelength
5.00X10^-19 J = 6.626X10^-34 Js (3.00X10^-8 m/s) / wavelength
wavelength = 3.97X10^-7 m = 397 nm
region is near ultraviolet (just below 400 nm visible range)