Another Physics Problem!?

Question

This question is from the forces unit:

A 50 kg crate is resting on the floor. the coefficient of friction between the floor and the crate is 0.5. a rope is attached to the crate is being pulled at an angle 25 above the horizontal. what is the largest force that can be applied to the rope that will allow the crate to stay at rest?

Answer 1

Favorite Answer

I'll go first, since no one else is here...

F  vertical ==>      N + F sin@ - mg = 0    [ two vert forces upwards...Normal Force  N  and  the vertical  component of the rope pulling up at @ = 25˚ ... one  down  ]

N = normal  force,  F sin@  = upward component of  Rope     mg  = weight

F  = horiz forces   ==>  F cos@ - µN = 0         so     N = (  F cos @  ) / µ

Replace  N     ( F cos @) / µ + F sin @ - mg = 0

you know  m, µ,  and  @

I'll let you plug in and solve for  F.... I got  about   219 Newtons

Answer 2

Surprising how many people get their education on Yahoo! Answers. Could be why the world is so screwed up nowadays.If you can't cook, get out of the kitchen.