Anonymous
Anonymous asked in Science & MathematicsChemistry · 3 weeks ago

Specific Heat Capacity Help!!?

11.0  J of heat is added to 10.00 g of gold, which is initially at 25°C.

The heat capacity of gold is 25.41 J/(mol • °C).  

What would be the final temperature of the gold?

after I convert to moles I get 0.0508

1 Answer

Relevance
  • 3 weeks ago

    (11.0  J) / (25.41 J/(mol • °C)) / (10.00 g Au / (196.966569 g Au/mol)) =

    8.53°C change

    25°C + 8.53°C = 33.5°C

    [Your number of moles is correct to 3 significant digits.]

Still have questions? Get your answers by asking now.