Physics Question help?
The figure shows 2 displacement vectors D1, and D2. The magnitude of the vectors are D1 = 28m, and D2 = 50m. The vectors make angles θ1 and θ2 with the x-axis shown in the figure. If θ1 = 42 degres and θ2 = 41 degrees find the magnitude of the net displacement vector D1 + D2 to the nearest meter? I'll see if I can add in a picture
The answer is 54m, but I'm trying tp figure out how
- AshLv 74 weeks ago
Using component method
sum of x-components of both vectors = 28cos42 + 50cos41
sum of y-components of both vectors = 28sin42 + 50sin41
Magnitude of Resultant vector = √[(28cos42 + 50cos41)² + (28sin42 + 50sin41 )²] = 78 m