A blacksmith quenches a horseshoe by dropping it in a water barrel. How much heat is lost to the water in the barrel as the 2.1 lb iron horseshoe cools from 1200℃ to 30℃. The specific heat of iron is 0.449 J/gC.
- Anonymous4 weeks ago
This question requires the formula q=mcT
q= amount of heat lost/gained (what we are solving for)
m= mass (in grams)
c= specific heat
and t= change in temperature (final temp - initial temp)
the mass of the horseshoe needs to be changed to grams first. (2.1 lbs is equal to 952.544 grams.)
then, we can plug the numbers into the equation.
X = (952.544 grams)(.449 J/gC)(30-1200 C)
X= -500399.9 Joules