i need math help asap?
Bruno's toy car is exactly similar to his father's real car. the ratio of the surface areas real car:toy car is 36:1
a. what is the ratio of the lenghts rael car:toy car?
i cannot solve this help-
(b) The real car has a luggage space of 0.54 m cubed
Calculate the luggage space in the toy car in cubic meters.
found out i cannot solve this part too :*) someone pls help
thanks, everyone who answered also sorry for spelling mistakes :) **lengths **real
- ?Lv 74 months agoFavorite Answer
a) To understand this, imagine or draw two squares.
The big square has side length 6 and area 6*6 = 36
The small square has side length 1 and area 1*1 = 1
The ratio of their sides is 6 to 1; the ratio of areas is 36 to 1.
It does not matter that the area on the cars are not on flat squares.
If the real:toy areas are 36: 1 then the ratio real:toy sides is 6:1
b) The ratio of two volumes is the cube of their sides ratio.
If a small to large area ratio is 1:36, then
the small to large side ratio is 1:6 and so
the small to large volume ratio is 1:6^3 = 1:216
That tells you that the luggage space in the toy car is
1/216 of the luggage space in the real car, so that is
0.54/216 = 0.0025 in cubic metres.
P.S. Spelling: LENGTHS REAL
- no sea naboLv 64 months ago
A=l✖w where cm✖cm=cm² and 36cm²:1cm²
now cm=√(cm²) so √(36cm²)=6cm, your answer "a)" is 6:1
- Anonymous4 months ago
a) is 1 to sq rt of 36 ie 1:6
b) is in ratio 1:6 x 6 x 6 which is 1:216
so luggage space on toy is 0.0025 cubic m
(real luggage space is 0.814 x 0.814 x 0.814m = 0.54 cubic m
reduce each linear dimension by factor of 6 and then calculate volume)