# i need math help asap?

Bruno's toy car is exactly similar to his father's real car. the ratio of the surface areas real car:toy car is 36:1

a. what is the ratio of the lenghts rael car:toy car?

i cannot solve this help-

Update:

(b) The real car has a luggage space of 0.54 m cubed

Calculate the luggage space in the toy car in cubic meters.

found out i cannot solve this part too :*) someone pls help

Update 2:

thanks, everyone who answered also sorry for spelling mistakes :) **lengths **real

Relevance

a) To understand this, imagine or draw two squares.

The big square has side length 6 and area 6*6 = 36

The small square has side length 1 and area 1*1 = 1

The ratio of their sides is 6 to 1; the ratio of areas is 36 to 1.

It does not matter that the area on the cars are not on flat squares.

If the real:toy areas are 36: 1 then the ratio real:toy sides is 6:1

b) The ratio of two volumes is the cube of their sides ratio.

If a small to large area ratio is 1:36, then

the small to large side ratio is 1:6 and so

the small to large volume ratio is 1:6^3 = 1:216

That tells you that the luggage space in the toy car is

1/216 of the luggage space in the real car, so that is

0.54/216 = 0.0025 in cubic metres.

P.S. Spelling: LENGTHS REAL

• A=l✖w where cm✖cm=cm² and 36cm²:1cm²

• Anonymous
4 months ago

a) is 1 to sq rt of 36 ie 1:6

b) is in ratio 1:6 x 6 x 6   which is 1:216

so luggage space on toy is 0.0025 cubic m

(real luggage space is 0.814 x 0.814 x 0.814m = 0.54 cubic m

reduce each linear dimension by factor of 6 and then calculate volume)