# The International Space Station orbits Earth at about 350km above Earth's surface.?

a) Determine the speed needed by the ISS to maintain orbit.

b) Determine the orbital period of the ISS in minutes.

### 1 Answer

Relevance

- oubaasLv 73 months agoFavorite Answer
a) Determine the speed Vo needed by the ISS to maintain orbit.

Vo^2/((3.72+0.35)*10^6) = Me*G / (((3.72+0.35)*10^6)^2

Me*G = 4*10^14 m^3/sec^2Vo^2*((3.72+0.35)*10^6) = 4*10^14

Vo = √ 4*10^14 / ((3.72+0.35)*10^6) = 9,914 m/sec (9910 with 3 sign. digits)

b) Determine the orbital period T of the ISS in minutes.

T = 2PI*((3.72+0.35)*10^6) / (Vo*60) = 6.2832*4.07*10^6/(9914*60) = 43.0 min

Still have questions? Get your answers by asking now.