If a projectile flies north at 423 meters in 6.8 seconds, what is its velocity?
- Anonymous1 month ago
Unable to determine, due to lack of vector data.
- Andrew SmithLv 71 month ago
Without comments it is extremely difficult to add to others statements. The velocity MUST include a direction. As NCS has done. If the projectile lands at this distance then there is no vertical displacement so the velocity over this time has NO vertical component. It is horizontal, 423/6.8 = 62 m/s North.
- 1 month ago
Idk if by north you mean up. If not, it should be irrelevant. If you mean displaced 423 meters horizontally, then its horizontal velocity is 62.2 m/s given the air resistance is negligible.
If you’re saying the projectile displaced 423 meters vertically, then its final velocity is 95.5 m/s and it’ll either be in the first or second half of its projectile motion. This is ignoring air resistance.
- NCSLv 71 month ago
423m [N] / 6.8s = 62 m/s [N]
as your velocity has both magnitude and direction.
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- AshLv 71 month ago
velocity = distance/time = 423 m / 6.8 s = 62.2 m/s
- billrussell42Lv 71 month ago
the horizontal component of the velocity is 423/6.8 m/s
the vertical component and total velocity are unknown.
- Bone AloneLv 71 month ago
423/6.8. Do the math.