If the mass defect for a radionuclide is –8.7839×10-30 kg, what's the binding energy per atom?

1 Answer

  • NCS
    Lv 7
    1 month ago

    E = mc² = 8.7839e-30kg * (2.99792e8m/s)² = 7.8946e-13 J

    or 4.9341 MeV

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